On Thu, May 24, 2001 at 05:19:34PM -0700, Andrew Sharp wrote: > That's correct. > > Scsibus0, id0, lun0 (if disk) == /dev/sda > Scsibus0, id0, lun1 (if disk) == /dev/sd[a+1] > . > . > Scsibus0, id1, lun0 (if disk) == /dev/sdN > . > . > scsibus1, id0, lun0 (if disk) == /dev/sdN+1 thought so. so all that tom needs to do is assign the nodename following this logic, however he will also need to test whether that device is a Direct-Acces or not. this can be done using the same wizardry i already use in scsiinfo(). (parsing /proc/scsi/scsi) it would make ofpath slower on devfs systems, but thats the price you pay for using devfs ;-) > and so on. If your external drive is on the same bus as your > internal drive, and you set the id on the external to 0 and the id > on the internal to 3, then guess what? Your external will be > /dev/sda and your internal will be /dev/sdb. That's the way it > works. You are in complete control of how the assignments are > made. If you're using a scsi setup where the id's are assigned > automatically by position on the bus (so called SCA connectors on > the drive(s)), then you can just move the drives around 'till > they're in the order you want. > > a -- Ethan Benson http://www.alaska.net/~erbenson/
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