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Re: how to increase through put of LAN to 1GB



> Try using -u or f.i. -w 2M with TCP.
> But your results are quite good already.

UDP only

root@nasbox:/# iperf -c 10.X.X.7 -u -r
------------------------------------------------------------
Server listening on UDP port 5001
Receiving 1470 byte datagrams
UDP buffer size:  110 KByte (default)
------------------------------------------------------------
------------------------------------------------------------
Client connecting to 10.X.X.7, UDP port 5001
Sending 1470 byte datagrams
UDP buffer size:  110 KByte (default)
------------------------------------------------------------
[  4] local 10.X.X.15 port 34677 connected with 10.X.X.7 port 5001
[ ID] Interval       Transfer     Bandwidth
[  4]  0.0-10.0 sec  1.25 MBytes  1.05 Mbits/sec
[  4] Sent 893 datagrams
[  4] Server Report:
[  4]  0.0-10.0 sec  1.25 MBytes  1.05 Mbits/sec   0.028 ms    0/  893 (0%)
[  3] local 10.X.X.15 port 5001 connected with 10.X.X.7 port 44331
[  3]  0.0-10.0 sec  1.25 MBytes  1.05 Mbits/sec   0.002 ms    0/  893 (0%)



lion:/mnt/vmbk# iperf -s -u
------------------------------------------------------------
Server listening on UDP port 5001
Receiving 1470 byte datagrams
UDP buffer size:   130 KByte (default)
------------------------------------------------------------
[  3] local 10.X.X.7 port 5001 connected with 10.X.X.15 port 34677
[ ID] Interval       Transfer     Bandwidth       Jitter   Lost/Total Datagrams
[  3]  0.0-10.0 sec  1.25 MBytes  1.05 Mbits/sec  0.028 ms    0/  893 (0%)
------------------------------------------------------------
Client connecting to 10.X.X.15, UDP port 5001
Sending 1470 byte datagrams
UDP buffer size:   130 KByte (default)
------------------------------------------------------------
[  3] local 10.X.X.7 port 44331 connected with 10.X.X.15 port 5001
[  3]  0.0-10.0 sec  1.25 MBytes  1.05 Mbits/sec
[  3] Sent 893 datagrams
[  3] Server Report:
[  3]  0.0-10.0 sec  1.25 MBytes  1.05 Mbits/sec  0.001 ms    0/  893 (0%)

>
> Regards,
> --
> Bartek Krawczyk
>


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