Re: #200264 and xmessage

[Stefan Ulrich <stefan-ulrich.nntp@zen.co.uk>]

Hilmar Preusse <hille42@web.de> writes:

> Little patch. The default message is that what we want. For any
> reason multi line messages don't work if the message is given at the
> command line with argv[1].

If you pass a string containing `\n', it's 2 characters instead
of the C escape sequence `\n'. Maybe one could pass a multi-line
argument to it ... otherwise you can replace it explicitly:

static char *
normalize_newline(const char *str)
{
    int i, k;
    for (i = 0, k = 0; str[i] != '\0'; i++, k++) {
	/* check for non-escaped `\n' */
	if (str[i] == '\\' && str[i + 1] == 'n'
	    && (i == 0 || (i > 1 && str[i - 1] != '\\'))) {
	    str[k] = '\n';
	    i++;
	}
	else {
	    str[k] = str[i];
	}
    }
}

and then in main:

    if (argc < 2) {
	fprintf(stderr, "Usage: %s message\n", argv[0]);
    }
    if ((msg = malloc(strlen(argv[1] + 1))) == NULL) {
	fprintf(stderr, "Couldn't allocate space for `%s'!\n", argv[1]);
	exit(1);
    }

    strcpy(msg, argv[1]);

    /* replace "\n" in msg (2 chars) by `\n' (one char) */
    msg = normalize_newline(msg);
    

-- 
Stefan Ulrich