Re: Nov 16 draft of voting mechanics

[Raul Miller <moth@debian.org>]

On Mon, Nov 18, 2002 at 04:24:22AM +1000, Anthony Towns wrote:
> Right. A tie is precisely when there are no uneliminated propositions (and
> thus no weakest uneliminated propositions that can be eliminated).

Consider a ballot with the options A, B, C, D, E.  E is the default
option.  The votes are:
10 DABC
 8 BCDE
 6 CDAB

D wins.

Now consider a ballot with additional options a, b, c, d.  The votes are:
5 DdAaBbCc
5 dDaAbBcC
4 BbCcDdAa
4 bBcCdDaA
3 CcDdAaBb
3 cCdDaAbB

This should result in a tie between d and D.

If you have no propositions for a tie, how can you tell which options
are involved in the tie?

Thanks,

-- 
Raul