[Date Prev][Date Next] [Thread Prev][Thread Next] [Date Index] [Thread Index]

Nov 16 draft of voting mechanics



More silliness fixed:  The word "tie" is now only used in one context.
The definition of "transitive defeats" is fixed.  The language defining
propositions has been cleaned up.

If anyone feels that draft is too hard to understand, please write me
a letter indicating the first part that you have trouble understanding,
and something about the nature of the problem you're having.


  A.6 Vote Counting

    1. Each ballot orders the options being voted on in the order
       specified by the voter.  If the voter does not rank some options,
       this means that the voter prefers all ranked options over the
       unlisted options.  Any options unranked by the voter are treated
       as being equal to all other unranked options.

    2. Options which do not defeat the default option are eliminated.

       Definition: Option A defeats option B if more voters prefer A
       over B than prefer B over A.

    3. If an option has a quorum requirement, that option must defeat
       the default option by the number of votes specified in the quorum
       requirement, or the option is eliminated.

    4. If an option has a supermajority requirement, that option must
       defeat the default option by the ratio of votes specified in the
       supermajority requirement, or the option is eliminated.  That is,
       if a an option has a 2:1 supermajority requirement, then there
       must be twice as many votes which prefer that option over the
       default option than there are votes which prefer the default
       option over that option.

    5. If one remaining option defeats all other remaining options,
       that option wins.

    6. If more than one option remains after the above steps, we use
       Cloneproof Schwartz Sequential Dropping to eliminate any cyclic
       ambiguities and then pick the winner.  This procedure and must
       be carried out in the following order:

       i. All options not in the Schwartz set are eliminated.

          Definition: An option C is in the Schwartz set if there is no
          other option D such that D transitively defeats C AND C does
          not transitively defeat D.

          Definition: An option F transitively defeats an option G if F
          defeats G or if there is some other option H where H defeats
          G AND F transitively defeats H.

       ii. Unless this would eliminate all options in the Schwartz set,
           the weakest propositions are eliminated.

           Definition: A proposition is a pair of options J and K
           from the Schwartz set which are considered along with
           the number of voters who prefer J to K and the number
           of voters who prefer K to J.

           Definition: The dominant strength of a proposition is the
           count of votes in a proposition which is not smaller than
           the other vote count in that proposition.

           Definition: a weak proposition is a proposition which
           has a dominant strength greater than zero and no larger
           than that of any other proposition.

           Definition: a weakest proposition is a weak proposition where
           the vote count in the proposition which is not larger than
           the other vote count is also no smaller than that of any
           other weak proposition.

           Definition: A proposition is eliminated by treating both
           of its vote counts as zero from this point forward.

       iii. If eliminating the weakest propositions would eliminate all
            votes represented in the Schwartz set, a tie exists and the
            person with the casting vote picks from among the options
            represented in this Schwartz set.

       iv. If eliminating the weakest propositions would not eliminate
           all votes, a new Schwartz set is found based on the newly
           revised set of propositions.

       v. If this new set of propositions allows one option to 
          defeat all other options in the Schwartz set, that
          option wins.

       vi. Otherwise, these steps (i-vi) are repeated with this new
           Schwartz set.


Thanks,

-- 
Raul



Reply to: