On Thu, 2003-04-17 at 18:15, Jochen Voss wrote: > > 5. If there are defeats between options in the Schwartz set, we ... > > 6. If there are no defeats within the Schwartz set, then .. > How could there be defeats within the Schwartz set at this point? Read 5 and 6 together. If there a defeats then (5), otherwise if there are no defeats then (6).