On Wed, Dec 18, 2019 at 10:38:26PM -0500, songbird wrote: > rhkramer@gmail.com wrote: > ... > >> if test -z "$home" -o \! -d "$home" ; then > > > > What does the -o \! do -- hmm, I guess \! is a bash "refeence" to the owner -- > no, -o is logical or in that context. Yes, exactly: it's not bash operating on that, but test [1], so for bash it's a plain old parameter passed to test. > the backslash is just protecting the ! operator > which is the not operator on what follows. Again, this is supposed to be passed to test unharmed, so the \ is telling bash "nothing to see here, pass along). > i'm not going to go any further with reading > whatever script that is. i don't want to be > here all evening. ;) Shell can be entertaining, can't it [2]? Cheers [1] Of course, this was a little white lie: there is a /bin/test, but for bash "test" is a built in, so it's part of bash anyway, but it behaves as if it were a binary. Oh, my ;-) [2] Recommended: Greg Wooledge's pages. He's a regular here. He knows much more about shells than me! https://mywiki.wooledge.org/ -- tomás
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