Bash variable escaping

[Denis Witt <denis.witt@concepts-and-training.de>]

Hi List,

I've a problem with a script. It's a wrapper for a program which uses
for example '*' as a parameter. It could also be 'foobar*' and I want
the script user to type in the desired parameter via "dialog
--inputbox".

The parameter is set correctly: "echo ${parameter}" gave me exactly what
I expect to see ('*'). Unfortunately when the parameter is passed to the
program it looks like this (according to "set +x"): 

/usr/bin/salt ''\''*'\''' state.highstate -v test=True -b 10

How can I avoid that?

Thanks in advance.

Bye for now.