Cameron Hutchison wrote: > This construct: > > some_cmd | while read var ; do > OTHER_VAR=... > done > > will result in OTHER_VAR being unset at the completion of the loop. That > is because the while command is on the right-hand side of the pipe > meaning it runs in a subshell. At the end of the while loop, the > subshell exits and any vars it sets will go away with it. And just to add, here are some references for further information. http://mywiki.wooledge.org/BashFAQ/024 http://mywiki.wooledge.org/SubShell And it is FAQ E4 in the Bash FAQ. ftp://ftp.cwru.edu/pub/bash/FAQ Bob
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