hendrik@topoi.pooq.com wrote: > I'd like to define a symbol ARCH in my Makefile to be the output > of > uname -m > > The obvious thing, just starting with > > ARCH = `uname -m` > > didn't seem to work. It defined ARCH to be `uname -m' instead of > i686 or x86_64. Not unreasonable, but What *is* the way to do > this? With GNU make you can use "ARCH = $(shell uname -m)". Regards, Dennis