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Re: simple bash loop problem ...



El(On) 28/06/2003 (15:03:27), David selby escribió(wrote):
> Hello,
> 
> I am writing bash a bash & sed script, it has been going suprisingly 
> well. I need a loop to count 9 times & the variable n to the count ..
> 
> for n=1 to 9
> ....
> next
> 
> kind of thing, but this is not BASIC !!
> 
> My best guess is
> 
> declare -i n=1
> while [ $n < 9 ]; do
> .....
> n=$((n+=1))
> done
> 
> All i get is ...
> 
> web@debian:/usr/local/myfiles/dave/websites/kcards$ ./gensite
> ./gensite: 9: No such file or directory
> 
> I have defined it as an integer, used the less than operator for 
> integers, ... errr ... I know its something stupid but I can't crack it ....
> 
> Dave
> 
> PS is there a more ellagent way to do a counted loop as well as a way 
> that works ?

Perhaps you can use:

        for n in `seq 1 9`; do
        ...
        done


Regards.

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