simple bash loop problem ...

[David selby <debian@pusspaws.net>]

Hello,

I am writing bash a bash & sed script, it has been going suprisingly 
well. I need a loop to count 9 times & the variable n to the count ..

for n=1 to 9
....
next

kind of thing, but this is not BASIC !!

My best guess is

declare -i n=1
while [ $n < 9 ]; do
.....
n=$((n+=1))
done

All i get is ...

web@debian:/usr/local/myfiles/dave/websites/kcards$ ./gensite
./gensite: 9: No such file or directory

I have defined it as an integer, used the less than operator for 
integers, ... errr ... I know its something stupid but I can't crack it ....

Dave

PS is there a more ellagent way to do a counted loop as well as a way 
that works ?