Re: use grep, egrep to print matched pattern?

[Uwe Zeisberger <zeisberg@informatik.uni-freiburg.de>]

On Thu, Jul 18, 2002 at 06:02:28PM +0200, Uwe Zeisberger wrote:
> Hello all
> 
> > > How can grep or egrep pattern in a file and print the pattern only? I
> > > will not print the whole line. e.g. to search the email address in
> > > /var/log/mail.log.  I am wondering is it possible to achieve this
> > > without writing a perl script?
> > 
> > Pipe the output to sed to trim the stuff on either side of the pattern.
> > 
> > grep 'localhost' myfile | sed 's/^\(.*?\)\(localhost\)\(.*?\)$/\2/'
> > 
> > or some such...
> i.e.
> 
> sed -n 's/.*\([^ ]*@[^ ]*\).*/\1/p' myfile

Oh, a mistake, use:

sed -n 's/.* \([^ ]*@[^ ]*\).*/\1/p' myfile

else Output _can_ contain

sdajfh user@domain.tld

(the solution of martin has the same prob)

Uwe

-- 
Uwe Zeisberger

$ dc << EOF
[1++2Q]sa[+1-1 2Q]sb[syd1-rly1-]sc[rd0=ard0=blcx]sd[ldxz1<e]se24872P3dn11296P4dn689978656Plexf
EOF


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