RE: Re.: Re: umount: /cdrom: devide is busy.
On 04-Oct-97 Alan Eugene Davis wrote:
>Thank you for the response. Perhaps I should clarify.
Open a new xterm and enter "ps -ef | grep cdrom" and if than returns
a line (or more) let us know what they are; if not, enter "df | grep
cdrom" and if that doesn't returm anything kill a white chicken by
the light of a full moon and after the feast, place its dried wish-
bone above your cdrom and say the magic words "Dennis M. Richie" (or
was that "Linus Torvalds") I can never remenber...
>
>I am using X. I have several xterms/rxvts open, and I am running
>several emacs frames. None of these, as far as I can tell, is
>connected in any way with /cdrom, neither sitting on it, nor
>accessing any file on the cd.
>
>I need to fing a way to find out which processes or xterms is/are
>causing this association to be made? This happens once in a while,
>that I am NOT in that directory, but I get this message, so something
>is going on that is not seen by me.
>
>Alan
>
>Dan Hugo writes:
>> This will always happen if, for example,
>>
>> pwd
>> /cdrom/*
>>
>> In other words, if you are IN the directory in question, it is busy.
>>
>> Happens to me all the time as well. Same with any mounts, or if you try
>> to rmdir a directory you are in.
>>
>> cd /;umount /cdrom
>>
>> should work
>>
>> -dh
>>
>>
>>
>>
>> Alan Eugene Davis wrote:
>> >
>> > This happens to me quite often: a floppy or a cd isn't being accessed,
>> > but I cannot unmount it: umount gives the error I have indicated.
>> >
>> > Is there any way to find out what process or which xterm might be
>> > accessing or sitting on a certain device?
>> >
>> > Thank you to all who have made my computing journey smoother.
>> >
>> > Alan
>> >
>> > --
>> >
>> > Alan E. Davis
>> > Marianas High School
>> > AAA196, Box 10001
>> > Saipan, MP 96950
>> > Northern Mariana Islands
>> > adavis@netpci.com
>> >
>> > " So that I can continue to use computers without dishonor, I have
>> > decided to put together a sufficient body of free software so that I
>> > will be able to get along without any software that is not free. "
>> > ---Richard Stallman
>> >
>> > --
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>>
>
>
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-----------------------------------------
Ralph Winslow rjw@nac.net
The IQ of the group is that of the member
whose IQ is lowest divided by the number
of members.
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