I'm confused: what's with atof?

[Randy Gobbel <gobbel@andrew.cmu.edu>]

Ok, I know the whole world can't have gone crazy overnight, so it must
be me.  This program:

#include <stdio.h>

int main(int argc, char **argv)
{
  char *sxxx = "1";
  int xxx = atoi(sxxx);
  char *sfoo = "1.0";
  double foo = atof(sfoo);
  double bar = 1.0;
  double zot = foo + bar;
        printf("xxx(%s) = %d, foo(%s) = %f, bar = %f, foo+bar = %f\n",
sxxx, xxx, sfoo, foo, bar, zot);
}

Does this:

xxx(1) = 1, foo(1.0) = 2147482232.000000, bar = 1.000000, foo+bar =
2147482233.000000

Note that the bizarre value that prints out is the same you'll get if
you type in "1.0" to one of the pastel/broken copies of emacs.  emacs is
actually calling atof, down in read1(lread.c).  But!  On every system
I've tried, this breaks in a similar way: atoi works fine, atof prints
out something weird, but reproducible.  I've tried this on Irix, x86
Linux, HP-UX, and LinuxPPC R4.

I'm obviously screwing up somehow (although you still have to wonder
about emacs).  What am I doing wrong?

-Randy
-- 
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