On 2022-06-27 at 10:31, Tim Woodall wrote: > Hi, > > apt-get --only-source --download-only source <package> > > will download the latest version of the source package. > > Is there a one liner that will give me the version of the package > (including the epoch) without downloading the package and parsing > the dsc? I'm not aware of one, just offhand; it'd be easy enough, except for the problem that version number comparison gets complicated in corner cases such as '+' and '~', and I'm not aware of a way to ensure that the version number comparison is done correctly without making it no longer a one-liner. (Well, short of putting the more complicated logic into a script and just running that script, but if you want a one-liner I assume that's not an option.) > ------ > Everything below here is what I've tried and problems I've > encountered - feel free to comment on this but the above is the > question that I'm particularly interested in whether there's a simple > answer to. > > > The filename doesn't include the epoch so I can't parse the output > of --print-uris. > > apt-cache showsrc <package> lists all of the versions available. I > can (and am) parsing that to find the highest version number. So... what is it that still needs to be done? I was putting together a possibly-kludgy easy-enough solution, and was running into the wall of needing to do pairwise comparisons (with 'dpkg --compare-versions') of the versions produced by 'apt-cache showsrc --only-source <package>', since any other comparison method isn't guaranteed to produce the same highest-version result as dpkg would use - but if you're already doing this, that looks like it solves the problem, for me. Is it just that your parsing makes this no longer a one-liner? -- The Wanderer The reasonable man adapts himself to the world; the unreasonable one persists in trying to adapt the world to himself. Therefore all progress depends on the unreasonable man. -- George Bernard Shaw
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