davidson wrote:
> >
> > I actually looked with `hd` and expected to see 0x20 there, but
> > somehow see none of it:
> >
> > $ echo $COMP_WORDBREAKS | hd
> > 00000000 22 27 40 3e 3c 3d 3b 7c 26 28 3a 0a |"'@><=;|&(:.|
> > 0000000c
>
> Above I count 12 characters piped from echo to hd. The final character
> is a newline added by echo, so that leaves 11 characters attributable
> to the content of COMP_WORDBREAKS.
>
> But try this, below. It will tell you the length (in characters) of
> the content of COMP_WORDBREAKS.
>
> $ echo ${#COMP_WORDBREAKS}
> 14
>
> So, when you do...
>
> $ echo $COMP_WORDBREAKS | hd
> 00000000 22 27 40 3e 3c 3d 3b 7c 26 28 3a 0a |"'@><=;|&(:.|
> 0000000c
>
> ...what accounts for the three missing characters (namely SPACE, TAB,
> and NEWLINE)?
>
> TLDR: The shell's "word splitting" removes them, because you have not
> double-quoted the variable.
Oh, I see. Thanks.
--
Victor Sudakov VAS4-RIPE
http://vas.tomsk.ru/
2:5005/49@fidonet
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