On 2018-12-19 09:12, mick crane wrote:
On 2018-12-19 08:34, deloptes wrote:mick crane wrote:yes but there is only one 100, only one key can have it. I still try to figure out what goes on with the hash pairs with a longer list of numbers your example seems to pick up on the values somehow. I dunno, unless there is something about using $_ in a loop being unreliable ? I persevere to succeed(1=>8,2=>20,6=>100,15=>100....)this is what you originally posted, so both 6 and 15 match 100 from the listwhen key is 6 it compares 100 with each element from the list and matches100. Same goes for 15. No idea what you mean! regardsgiven a set of *unique* numbers ( there is just one of the numbers in the list) and a list of possible pairings find which pairs you can make from the list.6 can pair with 100 and 15 can pair with 100 but they cannot both be in the list of possible pairings because there is only one 100.
just to be a bit clearer. given a list A of *unique* numbersand a list B of possible pairings find which pairs you can make from the list A.
6 can pair with 100 and 15 can pair with 100 but they cannot both be in the list of possible pairings because there is only one 100. -- Key ID 4BFEBB31