Re: 7z command works fine on command line but not in script

[berenger.morel@neutralite.org]

Le 19.02.2014 09:53, Scott Ferguson a écrit :
> On 19/02/14 19:47, berenger.morel@neutralite.org wrote:
> > Hello.
> >
> > I made a script to extract music from a jamendo archive, but for a
> > reason I do not know, 7z does not accept the command line. I also 
> > echoed
> > it, to be able to know what it tries to run, and it works fine when 
> > ran
> > on command line.
> >
> > Here is the script:
> >
> > #!/bin/sh
> >
> > for i in *.zip;
> > do
> >     artiste=`echo $i|cut -f1 -d-|sed -e 's/^ *//g' -e 's/ *$//g'`
> >     album=`echo $i|cut -f2 -d-|sed -e 's/^ *//g' -e 's/ *$//g'`
> >     mkdir "$artiste/$album" -p
> >     7z x \"$i\" -o\"$artiste/$album\" || rmdir "$artiste/$album" -p
> >     echo 7z x \"$i\" -o\"$artiste/$album\"
> > done
> >
> > With, for example, this archive:
> > http://www.jamendo.com/fr/list/a69778/monument, the folders are
> > correctly created, but it prints:
> > Error: Incorrect command line
> > 7z x "Shearer - Monument - a69778 --- Jamendo - MP3 VBR 192k.zip"
> > -o"Shearer/Monument"
> >
> > Do someone knows what I am doing wrong?
>
> Maybe passing "-" without a recognised qualifier (after the
> $artiste/$album\) ??
>
> Kind regards

It does not change anything.

I have some "progress", when I do this:
7z x "\'$i\'" -o"\'$artiste/$album\'"
instead of
7z x \"$i\" -o\"$artiste/$album\"

But the the error become "there is no such archive". I wonder if the 
easier would not be to try another unarchiver...