Re: Bash script - pass command line arg to embedded sed script with multiple args

[Daniel D Jones <ddjones@riddlemaster.org>]

On Saturday 17 April 2010 00:09:28 Michael Elkins wrote:
> On Fri, Apr 16, 2010 at 08:15:38PM -0400, Daniel D Jones wrote:
> >What I'm trying to do is pretty simple.  Getting it to work is turning out
> > not to be.  What I want to do is call a bash script with a couple of
> > arguments, and, within the script, call sed to use those args to replace
> > two placeholders in a file:
> >
> >bashscript SUB1 SUB2
> >
> >This line inside bashscript doesn't work:
> >
> >sed -e 's/PLACEHOLDER1/$1/' -e 's/PLACEHOLDER2/$2/' < input > output
> 
> If you switch the single quotes to double quotes it will work as you
>  expect. Variables inside of double quotes are expanded.  Single quotes are
>  for literal strings, as you've discovered.

That was the first thing I tried and sed gave me an error:

sed: -e expression #1, char 18: unknown option to `s'

I just went back and tried it again and it worked, so I have no idea what I 
did the first time that made it not work.

-- 
"Clear writers assume, with a pessimism born of experience, that whatever 
isn't plainly stated the reader will invariably misconstrue." - John R. 
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