On Thu, 2008-11-20 at 17:27 +0100, François Cerbelle wrote:
> Le Jeu 20 novembre 2008 16:18, tôba a écrit :
> > icon_3620_0_1.jpg
> > icon_3616_0_1.jpg
> > icon_3563_0_1.jpg
> >
> > The goal is to create a directory called 3620 and move the
> > icon_3620_0_1.jpg file into this directory.
> >
> > So, I did like this for test:
> > # for a in `ls | sed -e s'/_/ /g' | awk '{print $2}'`; do echo
> > icon_$a_0_1.jpg; done
>
> for a in `ls`; do DIR=`echo $a | cut -d_ -f2`; echo mkdir -p $DIR
> /$a; echo rmdir $DIR/$a; echo mv $a $DIR/$a; done
...
Why do this with a `ls` when a simple * will work?
for a in *; do ...
>
--
Bob McGowan
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