Re: using sizeof

[Mike McCarty <Mike.McCarty@sbcglobal.net>]

Jon Dowland wrote:
> > Because sizeof is not really the size of the struct, it is
> > the distance between adjacent structs in an array.
> > Alignment forces the extra bytes
>
>
> I'm not quite sure I get what you're saying here. Yes,
> alignment pads out the structure. But I'm not sure where
> arrays come into it :- sizeof(struct whatever) is applicable
> to a single instance of a struct too.

What he's saying is that

	struct FredStruct Fred[2];
	...
	sizeof(struct Fred[0])

is the same as

	(void *)(&Fred[1])-(void *)(&Fred[0])

Structures may get padding at the end precisely for this
reason. It is not obvious that this is the case when one
talks about a single instance.

Mike
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