Re: Printing the date just before execution of commands in bash

[José Alburquerque <jaalburquerque@cox.net>]

Roberto C. Sanchez wrote:
> On Thu, Oct 12, 2006 at 07:10:57PM -0400, José Alburquerque wrote:
>   
> > Hi all.  I'm wondering if anyone knows how I might be able to execute
> > the same command just before the execution of a command issued at the
> > prompt of a bash shell.
> >
> > Currently, I have my bash prompt set up so that it displays the current
> > date.  If I can print the date just before each command is executed, I
> > can always be able to get a sense of how long each command has taken.
> >
> > Anyone has any idea how I might go about printing the date just before
> > the execution of each bash command?  I just don't know where I would
> > start.  Thanks for any help.
> >
> >     
> Why not just use /usr/bin/time for the commands which you you want to
> time?
>
> Regards,
>
> -Roberto
>
>   
I guess I could do that, it's just that I use certain commands almost 
"instinctively" and sometimes I forget.  A lot of times I'm running 
certain processes one after the other in several shells.  It is after 
I've run them that I realize that it would have been nice to "time" some 
of them.

I suppose I could just be more attentive as to which commands I'd like 
to "time".  I'll keep what you say in mind. :-)

--
Sincerely
Jose Alburquerque