Re: Makefile parametrisation

[hendrik@topoi.pooq.com]

On Tue, Apr 25, 2006 at 06:56:27PM +0200, Dennis Stosberg wrote:
> hendrik@topoi.pooq.com wrote:
> 
> > I'd like to define a symbol ARCH in my Makefile to be the output
> > of
> >       uname -m
> >
> > The obvious thing, just starting with
> >
> > ARCH = `uname -m`
> >
> > didn't seem to work.  It defined ARCH to be `uname -m' instead of
> > i686 or x86_64.  Not unreasonable, but What *is* the way to do
> > this?
> 
> With GNU make you can use "ARCH = $(shell uname -m)".
> 
> Regards,
> Dennis

Thanks.  That worked.  Why do I need it?  Because I have just one home 
directory, NFS-mounted and shared between two machines with different 
architectures.  I find it convenient for everything except compiling.

-- hendrik