Re: Synaptic shows kernel 2.6.14 as obsolete. Why?
Hello
Edward C. Jones (<edcjones@comcast.net>) wrote:
> I have a PC with an AMD64 +3500 cpu chip. I use up-to-date debian
> unstable, "i386" distribution. I have two "vmlinuz"s:
> "/boot/vmlinuz-2.6.12-1-386" and "/boot/vmlinuz-2.6.14-2-386". The
> installed packages are "linux-image-2.6.12-1-386", version 2.6.12-10
> and "linux-image-2.6.14-4-386" version 2.6.14-7. By default, the
> system boots into 2.6.14.
>
> Why does Synaptic show 2.6.14 as being "installed (local or
> obsolete)"?
Because it is no longer available from any package source. The 2.6.14
packages in unstable have been replaces by 2.6.15, and 2.6.12 still
remains in testing.
> Which kernel is the best one for me to use:
> "linux-image-2.6-386", linux-image-2.6-686", "linux-image-2.6-k7",
> etc? (I want to keep the "i386" distribution.)
Depends on your processor. The kernel you choose will not affect the
rest of the packages. If you have a AMD Athlon/Duron or newer, you can
use the k7 kernel. If you have a Pentium (I think Pentium II or newer),
you can use the 686 kernel. Otherwise (386, 486, K6 or really old
Pentium) use the 386 kernel.
best regards
Andreas Janssen
--
Andreas Janssen <andreas.janssen@bigfoot.com>
PGP-Key-ID: 0xDC801674 ICQ #17079270
Registered Linux User #267976
http://www.andreas-janssen.de/debian-tipps-sarge.html
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