Re: find/replace in place
use sed -i s/foo/bar/ filename.
this will do the replacement in place, without any extra steps.
regards,
sac.
On 12/20/05, Gregory Seidman <gsslist+debian@anthropohedron.net> wrote:
> On Mon, Dec 19, 2005 at 03:38:23PM -0500, Tony Heal wrote:
> } I have a database name I want to replace inside of an xml file. I can do
> } this in several step using sed, but I would like to do it in a single step
> } using perl. This is what I have in sed and what does not work in perl.
> }
> } SED
> } #!/bin/bash
> } echo -n "Please enter the name of the new database: "
> } read syelledb
> } dbchange=`cat /tmp/data-sources.xml|grep database|cut -d ">" -f2|cut -d "<" -f1`
> } sed s/$dbchange/$syelledb/ /tmp/data-sources.xml > /tmp/data-sources.xml.tmp
> } mv /tmp/data-sources.xml /tmp/data-sources.xml.orig
> } mv /tmp/data-sources.xml.tmp /tmp/data-sources.xml
> [...]
>
> Why stoop to Perl for something so simple and easy, especially when you
> have already written the sed for it? After all, sed stands for Stream
> Editor and you just want a non-stream version of it... i.e. ed. So your new
> script is:
>
> #!/bin/bash
> echo -n "Please enter the name of the new database: "
> read syelledb
> dbchange=`cat /tmp/data-sources.xml|grep database|cut -d ">" -f2|cut -d "<" -f1`
> ed -s /tmp/data-sources.xml <<EOF
> 1,$s/$dbchange/$syelledb/g
> w
> q
> EOF
>
> Note that I added a 'g' to the end of the substitution command.
>
> } Tony Heal
> --Greg
>
>
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