BASH Scripting Question

[Metrics <the.metric@gmail.com>]

Hi all,

Can someone explain to me the following behaviour? I have this script

#!/bin/sh

LISTS=('debian-user' 'security-basics' 'hostap' 'pen-test' 'ntbugtraq' 'ion-general' 'vim' 'madwifi');
LIST_COUNT=${#LISTS}
echo $LIST_COUNT

for ((i=0;i<$LIST_COUNT-1;i++)); do
	echo /home/bhillis/Maildir/.${LISTS[${i}]}/
done

But when I run it I get...


11
/home/bhillis/Maildir/.debian-user/
/home/bhillis/Maildir/.security-basics/
/home/bhillis/Maildir/.hostap/
/home/bhillis/Maildir/.pen-test/
/home/bhillis/Maildir/.ntbugtraq/
/home/bhillis/Maildir/.ion-general/
/home/bhillis/Maildir/.vim/
/home/bhillis/Maildir/.madwifi/
/home/bhillis/Maildir/./
/home/bhillis/Maildir/./

Why does $LISTS have an extra two elements than I specified?

I'm following the guide from here
http://techrepublic.com.com/5100-1035_11-5820685.html?part=rss&tag=feed&subj=tr

Thanks in advance,

Byron Hillis
(Metrics)