Re: Bash commands

[Freddy Freeloader <fredddy@cableone.net>]

LOL.  I knew immediately after I sent that not saying that "a" was unset 
was a mistake.  Sorry. 

Stephen R Laniel wrote:

> On Thu, Oct 13, 2005 at 08:18:05AM -0700, Freddy Freeloader wrote:
>  
>
> > b=${a/23/BB}
> >
> > echo "b = $b"
> >
> > Now the ABS guide says that where I'm setting b it should be 
> > substituting BB for 23.  It also says that the output of 'echo "b - $b"' 
> > should be: b = BB35
> >    
>
> Well, it's taking whatever the value of $a is, and replacing
> 23 with BB. You didn't specify the value of $a before you
> run that substitution; what is it?
>
>