RE: simple bash loop problem ...
Google for 'bash loops'
http://www.google.com.au/search?q=bash+loops&ie=UTF-8&oe=UTF-8&hl=en&meta=
the first link is
http://www.tldp.org/HOWTO/Bash-Prog-Intro-HOWTO-7.html
Matt
--
> -----Original Message-----
> From: David selby [mailto:debian@pusspaws.net]
> Sent: Sunday, 29 June 2003 7:15 PM
> To: Debian list
> Subject: simple bash loop problem ...
>
>
> Hello,
>
> I am writing bash a bash & sed script, it has been going suprisingly
> well. I need a loop to count 9 times & the variable n to the count ..
>
> for n=1 to 9
> ....
> next
>
> kind of thing, but this is not BASIC !!
>
> My best guess is
>
> declare -i n=1
> while [ $n < 9 ]; do
> .....
> n=$((n+=1))
> done
>
> All i get is ...
>
> web@debian:/usr/local/myfiles/dave/websites/kcards$ ./gensite
> ./gensite: 9: No such file or directory
>
> I have defined it as an integer, used the less than operator for
> integers, ... errr ... I know its something stupid but I
> can't crack it ....
>
> Dave
>
> PS is there a more ellagent way to do a counted loop as well as a way
> that works ?
>
>
>
>
>
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