Re: Setting effective UID for a shell script
On Wed, May 15, 2002 at 05:17:41PM +0930, Tom Cook wrote:
> However, you are not entirely correct. This does, in fact, compile,
> with the exception of the type of execve for execv. It also, funnily
> enough, doesn't loop infinitely, which makes me think that the execv
> call is just failing. I am Interested, but not enough to figure out
> Why.
$ gcc -g -Wall -o suidscript suidscript.c
suidscript.c: In function `main':
suidscript.c:4: warning: passing arg 2 of `execve' from incompatible
pointer type
suidscript.c:4: too few arguments to function `execve'
$ ls suidscript
ls: suidscript: No such file or directory
Note: I said "semantically", since you pass argv[0] as the command to
execute, the program will keep executing itself (if argv[0] is fully
qualified). But, if you managed to get it to compile, it no doubt is
segfaulting due to noted errors above.
--
Eric G. Miller <egm2@jps.net>
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