Re: Just a question
On Thu, Aug 30, 2001 at 08:45:29PM -0700, Vineet Kumar wrote:
>
> * Brian Schramm (brian.schramm@ncmail.net) [010830 19:41]:
> > Is there a way that I can take a passwd file and compare the full name data
> > in it to the email ldap server and give a a list of what it finds and what it
> > misses? I am doing this manually but with the number of users that there are
> > involved it is going to be really time consuming.
>
> I don't really know what I'm talking about, but this should probably
> help you get started:
>
> awk -F : '{print $5}' /etc/passwd | sed -e "s/^\([^,]*\).*$/\1/"
>
> That will give you a list of just the full names. Pipe that into
> something else that will look each one up in the directory service.
>
> Not a complete answer, but it's a start...
BTW what does [ sed -e "s/^\([^,]*\).*$/\1/" ] accomplish? I'm just
grooving on one liners lately and am curious. It seems like -
awk -F : '{print $5}' /etc/passwd is all you need to spit out the full
names.
Thanks,
kent
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