libpcap0 question
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I've noticed that the Debian libpcap0 package comes with a shared object.
tomoe-hotaru:# dpkg -L libpcap0
(...)
/usr/lib/libpcap.so.0.6.2
(...)
My question then, is this? How/where did the .so file come from? When I
compiled libpcap 0.6.2 from source from www.tcpdump.org, all i got was a
libpcap.a file.
Since the program I'm working on is using the shared object, this made it
slightly annoying when I moved the files over to my laptop (which is not
using Debian, or really any existing distribution), as it only had the .a.
Now, I can statically compile libpcap in, but i didn't want to do this.
What I'm wondering, is how did Debian get the .so file, since there was no
switches or rules in the makefile for creating it out-of-the-tarball?
Any help would be appreciated.
- -- Curtis Hogg [buckminst@inconnu.isu.edu]
- ----------------------------------------------
The real reason psychology is hard is that psychologists are trying to
do the impossible.
- ----------------------------------------------
Email 1 - buckminst@inconnu.isu.edu
Email 2 - buckminst@hotmail.com
WWW - [in transit]
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