Re: C programming

["Eric G . Miller" <egm2@jps.net>]

I suggest going to comp.lang.c and checking the C FAQ. Specifically look
for the inherent problem of putting the same variable on both sides of a
relational operator: (x+y) > x

If memory serves, the behavior is "undefined" -- so don't do it!

On Fri, Aug 04, 2000 at 11:55:36PM +0200, Christophe TROESTLER wrote:
> Hi the list,
> 
> I apologize if that is a little bit off topic but I am a bit puzzled
> and  I  know there  are  experts  on this  list.   I  would like  an
> explanation on why the two "for" below give different results.
> 
> Thanks,
> ChriS
> 
> 
> -.¸¸.·´¯`·.¸¸.-.¸¸.·´¯`·.¸¸.-.¸¸.·´¯`·.¸¸.-.¸¸.·´¯`·.¸¸.-.¸¸.·´¯`·.¸¸.-
> 
> 
> #include <stdio.h>
> 
> main()
> {
>   double x, y, z;
>   int t;
>   
>   for(x=.5, y=1./4., t=1;   z= x + y, z > x;   y /=2,  t++)
>     ;
>   printf("t=%i\n", t);
> 
>   for(x=.5, y=1./4., t=1;  x+y > x;   y /=2,  t++)
>     ;
>   printf("t=%i\n", t); 
> }
> 
> 
> -- 
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> 
> 

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