On Tue, 25 Nov 1997, Stephen Zander wrote:
> "Eloy A. Paris" wrote:
> > Witold Grabysz <vtold@polsl.gliwice.pl> wrote:
> >
> > : the following phrase doesn't work in bash:
> > : ((ls);(ls))
> > : Why? Is it not allowed by the shell syntax or there is a bug in it?
> >
> > Yup, you're right; it's probably a bug. This does work:
> >
> > ( (ls);(ls))
> >
> > Try changing the definition of the helper in Netscape to follow the
> > above syntax.
>
> No, there's no bug in bash. ((<expr>)) indicates that arithmetic operations
> should be performed a la let x=i+1. Try this
>
> let i=5; while ((i>0)); echo $i; let i-=1; done
>
> The fix is right how ever; you need to disambiguate the expression.
You missed out the "do":
let i=5; while ((i>0)); do echo $i; let i-=1; done
...RickM...
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