On Wed, May 12, 2004 at 08:55:21PM +0100, Henning Makholm wrote: > I really don't see where you are getting at. Can you explain in little > words and with lots of intermediate results why you think that a GCC > modified for you hypothetical environment would be non-distributable? Because it incorporates functionality implemented in proprietary code. [This would be functionality you're not legally allowed to reverse engineer.] -- Raul