On 11/28/06, Shaun Jackman <sjackman@gmail.com> wrote:
I'm personally leaning towards to two arch: all packages (one 32-bit, one 64-bit) and a meta-package which depends on the right one. I am considering and open to the one arch: any package though. If it affects the decision, the binary package is roughly 1.2 MB.
I take it back. I implemented the arch: all method, and it wasn't that tricky, but the arch: any method is definitely technically simpler. Without a good reason, I can't see why I shouldn't use the simpler method. The argument for the arch: any case is obvious -- it's simpler -- what's the best argument for the arch: all case? Cheers, Shaun