Dear Arie, when upgradeing uuagc for Debian, I’d like to avoid packaging uuagc-bootstrap, as it is just a copy of uuagc (right?). Given that uuagc already exists in Debian, can a new uuagc packages build using that? If so, how? The documentation in Distribution.Simple.UUAGC seems to be outdated, but I cannot pass uuagc to uuagcLibUserHook. uuagc :: BuildInfo -> LocalBuildInfo -> PreProcessorSource uuagcLibUserHook :: ([String] -> FilePath -> IO (ExitCode, [FilePath])) -> UserHooksSource Main hook, argument should be uuagc function Thanks, Joachim -- Joachim "nomeata" Breitner Debian Developer nomeata@debian.org | ICQ# 74513189 | GPG-Keyid: 4743206C JID: nomeata@joachim-breitner.de | http://people.debian.org/~nomeata
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