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Avoiding uuagc-bootstrap

Dear Arie,

when upgradeing uuagc for Debian, I’d like to avoid packaging
uuagc-bootstrap, as it is just a copy of uuagc (right?). Given that
uuagc already exists in Debian, can a new uuagc packages build using
that? If so, how?

The documentation in Distribution.Simple.UUAGC seems to be outdated, but
I cannot pass uuagc to uuagcLibUserHook.

uuagc :: BuildInfo -> LocalBuildInfo -> PreProcessorSource

uuagcLibUserHook :: ([String] -> FilePath -> IO (ExitCode, [FilePath])) -> UserHooksSource
        Main hook, argument should be uuagc function 


Joachim "nomeata" Breitner
Debian Developer
  nomeata@debian.org | ICQ# 74513189 | GPG-Keyid: 4743206C
  JID: nomeata@joachim-breitner.de | http://people.debian.org/~nomeata

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