Re: gcc and multiple lines yield error: missing terminating " character message
Cem Vedat ISIK <cvi.list@gmail.com> writes:
> Hi all,
> I'm not really sure if here's the right place for this post, but I
> have a problem compiling my CGI apps with gcc ( version 4.0.2 20050808
> (prerelease) (Ubuntu 4.0.1-4ubuntu9) ) on Ubuntu. I've been using gcc
> version 4.0.3 20051201 (prerelease) (Debian 4.0.2-5) on my Debian
> system and without any problem I was able to compile a code that
> contains a segment like,
>
> printf( "
> <html><head>
> <META HTTP-EQUIV='expires' CONTENT='0'>
> <META HTTP-EQUIV='Cache-Control' CONTENT='no-cache'>
> <META HTTP-EQUIV='Pragma' CONTENT='no-cache'>
> " );
>
> But using the gcc in ubuntu, it says error: missing terminating "
> character and does not compile. I think that putting \ symbol at the
> end of each line will solve this, but I have thousands of lines of
> code, therefore it would not be a good idea, indeed.
> What may be the problem/solution for this case?
printf( "\n"
"<html><head>\n"
"<META HTTP-EQUIV='expires' CONTENT='0'>\n"
"<META HTTP-EQUIV='Cache-Control' CONTENT='no-cache'>\n"
"<META HTTP-EQUIV='Pragma' CONTENT='no-cache'>\n"
);
--
Falk
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