dpkg-source: nested *?+ in regexp at /usr/bin/dpkg-source line 771.
Well, anyone knows how to avoid this error in dpkg-source:
nested *?+ in regexp at /usr/bin/dpkg-source line 771.
ii dpkg-dev 1.4.0.17 Package building tools for Debian Linux
ii patch 2.1-11 Apply a diff file to an original
ii perl 5.004-1 Larry Wall's Practical Extracting and Report
ii bash 2.0-3 The GNU Bourne Again SHell
(all freshly installed, just to be sure).
$ dpkg-buildpackage -rsudo
dpkg-buildpackage: source package is libg++272
dpkg-buildpackage: source version is 2.7.2.5-2
dpkg-buildpackage: source version is joost witteveen <joost@rulcmc.leidenuniv.nl>
dpkg-buildpackage: build architecture is i386
sudo debian/rules clean
make clean
make[1]: Entering directory `/mnt/bigfoot/shome/joost/maintain/libg++/libg++272-2.7.2.5'
make[1]: *** No rule to make target `clean'. Stop.
make[1]: Leaving directory `/mnt/bigfoot/shome/joost/maintain/libg++/libg++272-2.7.2.5'
make: [clean] Error 2 (ignored)
make distclean
make[1]: Entering directory `/mnt/bigfoot/shome/joost/maintain/libg++/libg++272-2.7.2.5'
make[1]: *** No rule to make target `distclean'. Stop.
make[1]: Leaving directory `/mnt/bigfoot/shome/joost/maintain/libg++/libg++272-2.7.2.5'
make: [clean] Error 2 (ignored)
rm -f build
rm -rf ./debian/{tmp-shared,tmp-devel,tmp-debug}
#If I interrupt the build process, the next clean doesn't seem to work.
#rm -f libg++/gperf/src/gperf libio/dbz/rdbz.c libio/dbz/rdbzmain.c
#find . -name "*.o" -o -name "*.so*" -o -name "*.a" -o -name "*~"\
# -o -name "Makefile" -o -name "config.status" |xargs rm -f
dpkg-source -b libg++272-2.7.2.5
dpkg-source: building libg++272 using existing libg++272_2.7.2.5.orig.tar.gz
/^libg++272-2.7.2.5.orig/: nested *?+ in regexp at /usr/bin/dpkg-source line 771.
Thanks,
--
joost witteveen, joostje@debian.org
#!/usr/bin/perl -sp0777i<X+d*lMLa^*lN%0]dsXx++lMlN/dsM0<j]dsj
$/=unpack('H*',$_);$_=`echo 16dio\U$k"SK$/SM$n\EsN0p[lN*1
lK[d2%Sa2/d0$^Ixp"|dc`;s/\W//g;$_=pack('H*',/((..)*)$/)
#what's this? see http://www.dcs.ex.ac.uk/~aba/rsa/
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