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Re: RFC: new policy on dependencies between distributions (was Re: need decision on packages with crypto hooks)



On Sat, 29 Mar 1997, Andreas Jellinghaus wrote:

> Christian Schwarz wrote:
> ...
> > The rules:
> > 
> > o Every package in the free (main) distribution may only Depend or
> > Recommend packages in the free distribution.
> > 
> > o Every package in the non-free distribution may only Depend or Recommend
> > packages in the main or non-free distribution.
> >
> > o Every package in the non-us distribution may only Depend or Recommend
> > packages in the main or non-us distribution.
> > 
> > o Any other package has to go into the contrib distribution.
> 
> by current policy a program goes into non-free, if it's policy doesn't
> permit to put it on cdrom. even if it depends on a contrib program, you
> still have to put it in non-free. that's because you can put contrib on
> a cd-rom, but not non-free.

No, that's not right. There are "contrib" packages that have some
copyright restrictions (koules, picasm, etc.) that you can't put on a
CD-ROM. And according to the current Policy Manual, section 2.3 states
that "Packages which depend for their use on non-free or contrib packages
may only be placed in the semi-supported contrib section".

> if a program is in non-us, but requires a non-free program, you may
> still not put it into contrib, because of it's non-us status.

Right. I thought that the license question has priority over the above
dependency rule. Was this unclear?

> you can, of course proced as above, but spliting contrib into 3 parts:
> contrib, contrib/non-free and contrib/non-us. (or spliting non-free and
> non-us in the non-free respective non-us part and a non-free/contrib
> respective non-us/contrib part). 

I thought that "contrib/non-free" actually is "contrib" (as far as I
understood the policy, everything that is not "free" nor "non-free" is
"contrib" with the possible exception of "non-us") and that
"contrib/non-us" is "non-us". 

That's another point: non-us doesn't have a stable/unstable seperation.

> > o Every package may Suggest or Conflict with any other package, no matter
> > in which distribution they are.
> > 
> > 
> > Examples (can be used as references):
> > 
> > o A free package depending on a non-free package has to go to contrib. 
> > 
> > o A free or non-free package depending on a non-us package has to go to
> > contrib. For example the crpyto-hook package "pinepgp" is free (GPL) but
> > certainly depends on PGP, so it has to go into contrib.
> 
> a non-free package goin into contrib ? that's a) violates current policy
> and b) a cdrom vendor cannot put contrib on cdrom. as far as i know,
> current contrib can included in a cdrom (all packages, that may not
> included in a cdrom are in non-free).

We differ here. What's the opinion of the others?

Actually I _am_ a cdrom vendor so I had a look which packages I could
include. I checked all licenses in the non-free and contrib section and
decided _not_ to include three packages out of contrib: ferret (no license
included), koules, and picasm.

> > Any comments?
> 
> a package has 
> a) a distribution	: stable/ unstable/ tested
> b) a cdrom-marker	: free / non-free
> c) a contrib-marker	: free / contrib (only for free packages)
> d) a crypt-marker	: ok-in-us / non-us
> f) a depends-marker	: normal / "depends" (package depends/requires 
> 	something not in his distribution or in the free distribution).
> 
> i don't know, how to solve this problem, but it's not simple.
> at least: don't put something that is "non-free" or "non-us" into
> contrib, even if it depends on a "contrib" program".

That's a very systematic approach which is perhaps too complicated for our
situation. Consider that there are only 8 packages in non-us. 

> > I would like to add something like this to the Policy Manual.
> > 
> 
> o Every package in the free (main) distribution may only Depend or
> Recommend packages in the free distribution.
> 
> o If a package is non-free (see policy) it has to go into non-free.
> 	(yes, it may depend/recommend a package in contrib).
> 
> o If a package is non-us (see policy) it has to go into non-us.
> 	(yes, it may depend/recommend a package in contrib).
> 
> o Any other package has to go into the contrib distribution.

To summerize: I used the following order of distributions:

	   free
     non-free / non-us
         contrib

where you prefer the order

	    free
     non-free / contrib / non-us

> this will result in :
> 
>  - packages in non-free might depend on contrib programs.
>  - packages in non-us might depend on contrib programs.
>  - packages in contrib might depend on contrib programs.
> 
> yes, this is the current situation, and it causes trouble, but the other
> alternative i see, is to use 5 markers for 
>  - distribution
>  - cdrom-status
>  - crypto-status
>  - contrib-status 
>  - depends-status
> 
> currently we have a bix mix (unstable/stable/frozen/non-free/contrib/non-us).
> "contrib" says nothing about stability, "non-free" says nothing about
> depending on a contrib program or not etc.
> 
> restrictions:
> a program will never by "non-free" and "non-us" (i hope).
> we don't distinguish between unstable,stable,tested for non-us programs.
> 
> so we have to move from one marker to 3 markers. this will result in
> method a)				method b)
> unstable				free/official/unstable
> stable					free/official/stable
> tested					free/official/tested
> contrib/unstable			free/contrib/unstable
> contrib/stable				free/contrib/stable
> contrib/tested				free/contrib/tested
> non-free/unstable			non-free/official/unstable
> non-free/stable				non-free/official/stable
> non-free/tested				non-free/official/tested
> non-free/contrib/unstable		non-free/contrib/unstable
> non-free/contrib/stable			non-free/contrib/stable
> non-free/contrib/tested			non-free/contrib/tested
> non-us					non-us/official
> non-us/contrib				non-us/contrib
> 
> it might take some work, but improving our current system with only one
> marker for everything is importend (IMO).

This just makes it more complicated. What about mixing non-free and
contrib? (Hope this brave question doesn't start a flamewar :-)


Cheers,

Chris

--          _,,     Christian Schwarz
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           !   ___;   schwarz@debian.org, schwarz@mathematik.tu-muenchen.de
           \  /        
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