Re: much nicer, more complete matrix

[nick black <nick.black@sprezzatech.com>]

Karl Goetz left as an exercise for the reader:
> On Sat,   2 Feb 2013, 11:59:09 LHST, nick black <nick.black@sprezzatech.com> wrote:
> 
> > Paul Wise left as an exercise for the reader:
> > > pabs@chianamo ~ $ if dpkg --compare-versions 1.0-10 '<' 1.0-1SprezzOS1
> > > ; then echo true ; else echo false ; fi
> > > false
> > 
> > Disproof of one case does not a proof make :).
> > 
> > [skynet](0) $ if dpkg --compare-versions 1.0-1A '<' 1.0-1SprezzOS1 ; then
> > echo true ; else echo false ; fi
> > true
> > [skynet](0) $ 
> 
> from what i can tell you just showed that 1S is larger then 1A, but surely thats not a surprise.?

It is not a surprise. It does mean that there is no complete solution to the
original problem, that of encoding the original debian revision R into a new
debian revision R_A such that any change to the original debian revision R
results in a debian revision R_B such that ∀ R_B > R_A.

For the vast majority of plausible cases, though, the Ubuntu method works
just fine (as illustrated by Paul Wise).

-- 
nick black     http://www.sprezzatech.com -- unix and hpc consulting
to make an apple pie from scratch, you need first invent a universe.