Hi, Raul Miller: > [This is my second attempt at sending this message.] > The first attempt didn't make it, apparently. > c. An option, A, defeats an option, B, if N(A,B)*V(A,B) is > larger than N(A,B)*V(B,A), and the (A,B) defeat has not > been dropped. This does not make sense. One of the N(A,B)s needs to be N(B,A). > e. If a majority of n:1 is required for A, and B is the default > option, N(B,A) is n. In all other cases, N(B,A) is 1. I would generalize that to n:m (a 60% majority is 3:2, for instance). > 4. If there are defeats within the Schwartz set, we drop the weakest > such defeats, and return to step 4. > Step 3 -- you need to construct a new Schwartz set! -- Matthias Urlichs | noris network AG | http://smurf.noris.de/
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