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Re: supermajority options



Hello,

On Sat, Nov 23, 2002 at 09:23:42AM -0500, Raul Miller wrote:
> Cases where the default option defeats another option are never the
> weakest defeats.
Huh?  Can you explain this to me?  Why could this be true?

Confused,
Jochen
-- 
                                         Omm
                                      (0)-(0)
http://www.mathematik.uni-kl.de/~wwwstoch/voss/privat.html

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