Re: Bash argument expanded inside alias
Dear Clive, dear Tom,
Thanks for your time!
The solution:
mudafct() { find . -name "*" -mtime -$1; }
alias muda='mudafct'
seems to works inside .bashrc file! (Just 'seems' because I did not
reboot, just typed in a terminal and it worked great!)
Thanks both,
Beco.
To: debian-user@lists.debian.org
Subject: Re: Bash argument expanded inside alias
From: Clive Standbridge <list-user@tgstandbridges.plus.com>
Date: Tue, 13 Mar 2012 15:49:52 +0000
> does not work to do what your intuition imagine what I want it to do?
Hi Beco,
It doesn't work because aliases don't take arguments.
You can use a shell function instead. For example,
muda()
{
find . -name "*" -mtime -$1
}
--
Cheers,
Clive
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