[Date Prev][Date Next] [Thread Prev][Thread Next] [Date Index] [Thread Index]

Bug#508009: guess I'm stuck with Ubuntu apt.sources



I've been waiting, and waiting, and waiting for some sign that Debian
plans to support python 3. I understand the (apparent) decision to
wait until python 3.1. Debian is the new OpenBSD, and doesn't include
new versions of packages promptly if doing so would threaten the
stability of any existing application of any existing version of that
package.

With a package as fundamental to the Debian system as python, it's no
surprise that an entire new version (3.0) might simply be allowed to
fall by the wayside. Python 3 has numerous subtle bugs, I understand,
and if the process of developing safeguards against them would take
the Debian team longer than it will take the Python team to release a
newer, BugFree(tm) minor version number, the conservative decision is
surely to let python 3 spend some more time in the oven before
officially supporting it.

All of that said, I find this nondecision on Debian's part
frustrating. I'm a Debian user from way back, but no kind of Debian
developer. I come to you for the most well-organized distro out there,
and I was surprised when python 3 simply never appeared on your radar
(experimental). I'm still waiting.

Fortunately for me the Ubuntu team is more liberal than Debian, and
was willing to package python3 straightaway. It really hasn't
threatened the stability of my system at all, guys, any more than
Psyco or PyPy or another nonstandard python version would. I don't get
what the big deal is.

It would be gracious if you could see your way to making python3.0
packages available in some (any) form, however neutered. Meanwhile I'm
making do with an Ubuntu-Debian hybrid system. I don't like doing it,
but Debian has let me down.

Kerne
-- 
print apply(lambda p=[2]: filter(lambda n: p.append(n) if
all(map(long(n).__mod__,
p)) else None, range(2,450)) or apply(lambda s=''.join(map (lambda c: '_'*int(c)
if c.isdigit() else c, "1o95u4n5a6t3p y1J1
1rs1t6e94h91.t4r7k1e5h1c1a7n3 1o3h")):
''.join(map( s.__getitem__, (p[58+i] % p[14 +i] for i in range(27))))))



Reply to: