Re: Vote analysis

[Kalle Kivimaa <killer@debian.org>]

Anthony Towns <aj@azure.humbug.org.au> writes:
> That's not really legitimate STV since when a vote ranks two candidates
> equally I count it towards both totals, which is why 231+237 = 468 which
> is more than the total number of votes (421), but it's the best we can
> do, I think.

Nah, here are the results from my WebVoter voting system
(http://webvoter.killeri.net):

Round: 1, Q=210.50000, V=421.00000, P=1
Candidate 1 has 54.20952 votes
Candidate 2 has 7.30952 votes
Candidate 3 has 105.04285 votes
Candidate 4 has 138.34285 votes
Candidate 5 has 59.70952 votes
Candidate 6 has 2.34285 votes
Candidate 7 has 40.04285 votes
Candidate 8 has 14.00000 votes
Dropping candidate 6

Round: 2, Q=210.50000, V=421.00000, P=1
Candidate 1 has 55.28333 votes
Candidate 2 has 7.33333 votes
Candidate 3 has 105.11666 votes
Candidate 4 has 138.36666 votes
Candidate 5 has 59.78333 votes
Candidate 7 has 41.11666 votes
Candidate 8 has 14.00000 votes
Dropping candidate 2

Round: 3, Q=210.50000, V=421.00000, P=1
Candidate 1 has 56.05000 votes
Candidate 3 has 106.88333 votes
Candidate 4 has 142.63333 votes
Candidate 5 has 60.05000 votes
Candidate 7 has 41.38333 votes
Candidate 8 has 14.00000 votes
Dropping candidate 8

Round: 4, Q=207.50000, V=415.00000, P=1
Candidate 1 has 58.25000 votes
Candidate 3 has 107.08333 votes
Candidate 4 has 144.83333 votes
Candidate 5 has 63.25000 votes
Candidate 7 has 41.58333 votes
Dropping candidate 7

Round: 5, Q=206.50000, V=413.00000, P=1
Candidate 1 has 65.50000 votes
Candidate 3 has 122.33333 votes
Candidate 4 has 151.66666 votes
Candidate 5 has 73.50000 votes
Dropping candidate 1

Round: 6, Q=205.00000, V=410.00000, P=1
Candidate 3 has 148.50000 votes
Candidate 4 has 169.00000 votes
Candidate 5 has 92.50000 votes
Dropping candidate 5

Round: 7, Q=201.50000, V=403.00000, P=1
Candidate 3 has 198.50000 votes
Candidate 4 has 204.50000 votes
Candidate 4 provisionally elected

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