On Fri, Dec 01, 2000 at 06:54:32AM -0500, Raul Miller wrote:
> However, with the 3:1 supermajority which affects A, you get:
> 10 : 0 B:C
> 3 1/3: 0 A:B
> 3 1/3: 0 A:C
> B wins.
This isn't correct: A wins by being preferred to all other options (A >
B, 3.3 to 0 and A > C, 3.3 to 0). The strengths of the victories don't
come into play unless you have a cycle.
Cheers,
aj
--
Anthony Towns <aj@humbug.org.au> <http://azure.humbug.org.au/~aj/>
I don't speak for anyone save myself. GPG signed mail preferred.
``Thanks to all avid pokers out there''
-- linux.conf.au, 17-20 January 2001
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