* 2023-12-17 10:58:28+0000, Andy Smith wrote:
> On Sun, Dec 17, 2023 at 10:12:11AM +0000, Albretch Mueller wrote:
>> you get seconds in dt00 and dt02 and then the difference. You can't
>> go: $(( dt02 - dt00 )) because bash Arithmetic is 10-based.
>
> Why don't you just get the time as epoch time e.g. "date +%s" and
> then you can subtract one from the other¹.
Also, Bash has variable EPOCHSECONDS which expands to the current Unix
epoch time.
$ echo $EPOCHSECONDS; sleep 5; echo $EPOCHSECONDS
1702812641
1702812646
--
/// Teemu Likonen - .-.. https://www.iki.fi/tlikonen/
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