Re: Extract substring from cat
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On Fri, Oct 16, 2015 at 02:54:25PM +0200, Nemeth Gyorgy wrote:
> 2015-10-16 14:15 keltezéssel, Alfred Charles Stockton írta:
> >
> > If I issue the command cat /etc/*-release on my Debian system I get:-
> >
> > PRETTY_NAME="Debian GNU/Linux 8 (jessie)"
> > NAME="Debian GNU/Linux"
> > VERSION_ID="8"
> > VERSION="8 (jessie)"
> > ID=debian
> > HOME_URL="http://www.debian.org/";
> > SUPPORT_URL="http://www.debian.org/support/";
> > BUG_REPORT_URL="https://bugs.debian.org/";
> >
> > Now what I would like to do is to only print the substring "Debian
> > GNU/Linux 8 (jessie)" from the 1st line, preferably in bash.
> >
> > Please tell me how I should go about this?
> >
> > --
> > Regards,
> > Alf Stockton
> >
> >
> >
> cat /etc/*-release | grep ^PRETTY_NAME | sed 's/^.*=//'
Many insightful answers have been given. Yours is an example of "useless
use of cat" [1], better spelt as
grep ^PRETTY_NAME /etc/*-release | sed 's/^.*=//'
Even better, since sed can do grep:
sed -ne '/^PRETTY_NAME=/ s/^.*=// p' < /etc/*-release
[1] <http://uselessuseofcat.com/>
regards
- -- t
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